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Bumped by Community user
Bumped by Community user
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m_goldberg
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Inverse Finding the symbolic inverse of a function

Is there a way of inverting this function to obtain $r(\rho)$?

rho[r_, b0_, q_] := 
  r (1 + (Sqrt[\[Pi]]Gamma[1Sqrt[π]Gamma[1/(q - 1)])/((1 - q) Gamma[1/2 ((q + 1)/(q - 1))]) b0 /r + (1 + q)/(2 q) (b0/r)^(1 - q))

Note that $q<0$ and $b0$ is some positive constant.

Inverse of a function

Is there a way of inverting this function to obtain $r(\rho)$?

rho[r_, b0_, q_] := r (1 + (Sqrt[\[Pi]]Gamma[1/(q - 1)])/((1 - q) Gamma[1/2 ((q + 1)/(q - 1))]) b0 /r + (1 + q)/(2 q) (b0/r)^(1 - q))

Note that $q<0$ and $b0$ is some positive constant.

Finding the symbolic inverse of a function

Is there a way of inverting this function to obtain $r(\rho)$?

rho[r_, b0_, q_] := 
  r (1 + (Sqrt[π]Gamma[1/(q - 1)])/((1 - q) Gamma[1/2 ((q + 1)/(q - 1))]) b0 /r + (1 + q)/(2 q) (b0/r)^(1 - q))

Note that $q<0$ and $b0$ is some positive constant.

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Inverse of a function

Is there a way of inverting this function to obtain $r(\rho)$?

rho[r_, b0_, q_] := r (1 + (Sqrt[\[Pi]]Gamma[1/(q - 1)])/((1 - q) Gamma[1/2 ((q + 1)/(q - 1))]) b0 /r + (1 + q)/(2 q) (b0/r)^(1 - q))

Note that $q<0$ and $b0$ is some positive constant.