Timeline for What is wrong with my approach to solving a heat transfer PDE?
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 20, 2020 at 5:01 | comment | added | A little mouse on the pampas | 2++,Great answer . | |
| Jan 21, 2019 at 22:09 | history | edited | Nasser | CC BY-SA 4.0 |
typo
|
| Jan 21, 2019 at 22:00 | history | edited | Nasser | CC BY-SA 4.0 |
fixed math problem
|
| Jan 21, 2019 at 21:12 | comment | added | Moreza7 | @Nasser When using [0 , Pi] interval in integrating, there should be a 2 factor because we changed [-Pi, Pi] to [0, Pi] so the Mathematica is right. I don't know why you didn't used the 2 factor. | |
| Jan 21, 2019 at 20:50 | comment | added | Moreza7 | @Nasser Thank You. But using Mathematica for Fourier series coefficient: FourierCosCoefficient[Sin[x] - (x - ((x^2)/Pi)), x, 0] gets: 4/Pi - Pi/3 which is twice as yours: 2/Pi-P/6 why? | |
| Jan 21, 2019 at 20:30 | comment | added | Moreza7 | The B1 must be zero. How it is 2/Pi?! | |
| Jan 20, 2019 at 6:58 | history | edited | Nasser | CC BY-SA 4.0 |
fixed small typo in latex
|
| Jan 19, 2019 at 19:31 | history | edited | Nasser | CC BY-SA 4.0 |
removed the scaling issue. not needed
|
| Jan 19, 2019 at 0:22 | vote | accept | Moreza7 | ||
| Jan 18, 2019 at 19:42 | comment | added | Bill Watts | The premise that only having neumann boundary conditions makes the solution non-unique does not apply to the heat equation. There are numerous examples all over the web. One is found at ramanujan.math.trinity.edu/rdaileda/teach/s12/m3357/lectures/…. For some pde's the premise is correct, but different pde's have different bc requirements. By the way, separation of variables works very well in this case, but you do have to use plus separation as well as times separation to get all the pieces. | |
| Jan 18, 2019 at 7:36 | comment | added | Bill Watts | Changing the coefficient of t is not the same as adding any number to the solution. And indeed, changing that coefficient does not effect the bc's or ic's, but it breaks the pde. | |
| Jan 18, 2019 at 5:48 | comment | added | Mariusz Iwaniuk | 1++,Great answer . | |
| Jan 18, 2019 at 4:31 | history | edited | Nasser | CC BY-SA 4.0 |
fixed typo
|
| Jan 18, 2019 at 4:06 | history | answered | Nasser | CC BY-SA 4.0 |