Timeline for What is wrong with my approach to solving a heat transfer PDE?
Current License: CC BY-SA 4.0
8 events
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| Jan 18, 2019 at 16:16 | history | edited | Mariusz Iwaniuk | CC BY-SA 4.0 |
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| Jan 18, 2019 at 16:01 | history | edited | Mariusz Iwaniuk | CC BY-SA 4.0 |
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| Jan 18, 2019 at 10:30 | comment | added | xzczd♦ | @Nasser and Mariusz …This solution is incorrect, just compare it to the numeric solution. | |
| Jan 18, 2019 at 1:10 | comment | added | Bill Watts |
Adding a constant to the stated solution will break the ic u[x,0] = Sin[x]. I think that the given ic is enough to make the solution unique.When you work the solution with separation of variables there are no extra constants lying around.
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| Jan 18, 2019 at 0:57 | comment | added | Nasser |
good answer. Yes, this seems like a valid solution. But it is not unique solution as adding any number to the solution is also a solution. D[(10 + MAPLESOL) /. Infinity -> 20 // Activate, x] /. t -> 0 /. x -> 0 gives 1 as well. May be Mathematica did not solve it because of this? I do not know. Maple 2018 generally can solve more PDE's than Mathematica 11.3
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| Jan 17, 2019 at 21:49 | vote | accept | Moreza7 | ||
| Jan 19, 2019 at 0:22 | |||||
| Jan 17, 2019 at 21:23 | history | edited | Mariusz Iwaniuk | CC BY-SA 4.0 |
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| Jan 17, 2019 at 21:16 | history | answered | Mariusz Iwaniuk | CC BY-SA 4.0 |