Post Closed as "unclear what you're asking" by corey979, bobthechemist, bbgodfrey, Niki Estner, Αλέξανδρος Ζεγγ
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I have a function $f(x,y) = \sin(x) \cos(y) e^{x+y}$$ f(x, y) = \sin x\ \cos y\ \mathrm e^{x + y} $ (just an example) such that $x + y \le 1$$ x + y \le 1 $ (both $x$$ x $ and $y$$ y $ are positive and $0<x\le 1$$ 0 < x \le 1 $ and $0< y \le 1$$ 0 < y \le 1 $). 

I want to make a contour plot such that the contraint $x + y \le 1$$ x + y \le 1 $ is taken into consideration. By this I mean that for the value of $x=x_0$$ x = x_0 $ the values of $f$$ f $ should be such that $y=1-x_0$$ y = 1 - x_0 $.

I have a function $f(x,y) = \sin(x) \cos(y) e^{x+y}$ (just an example) such that $x + y \le 1$ (both $x$ and $y$ are positive and $0<x\le 1$ and $0< y \le 1$). I want to make a contour plot such that the contraint $x + y \le 1$ is taken into consideration. By this I mean that for the value of $x=x_0$ the values of $f$ should be such that $y=1-x_0$.

I have a function $ f(x, y) = \sin x\ \cos y\ \mathrm e^{x + y} $ (just an example) such that $ x + y \le 1 $ (both $ x $ and $ y $ are positive and $ 0 < x \le 1 $ and $ 0 < y \le 1 $). 

I want to make a contour plot such that the contraint $ x + y \le 1 $ is taken into consideration. By this I mean that for the value of $ x = x_0 $ the values of $ f $ should be such that $ y = 1 - x_0 $.

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Regarding a contour plot

I have a function $f(x,y) = \sin(x) \cos(y) e^{x+y}$ (just an example) such that $x + y \le 1$ (both $x$ and $y$ are positive and $0<x\le 1$ and $0< y \le 1$). I want to make a contour plot such that the contraint $x + y \le 1$ is taken into consideration. By this I mean that for the value of $x=x_0$ the values of $f$ should be such that $y=1-x_0$.