Timeline for Solve a system of 4-th order polynomial equations (numerically)
Current License: CC BY-SA 4.0
10 events
when toggle format | what | by | license | comment | |
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Nov 11, 2018 at 15:00 | history | tweeted | twitter.com/StackMma/status/1061634770357153794 | ||
Nov 11, 2018 at 14:24 | vote | accept | apt45 | ||
Nov 11, 2018 at 7:19 | history | edited | Αλέξανδρος Ζεγγ | CC BY-SA 4.0 |
added 117 characters in body
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Nov 11, 2018 at 2:31 | answer | added | Michael E2 | timeline score: 1 | |
Nov 10, 2018 at 22:17 | comment | added | Michael E2 | Possible duplicate: mathematica.stackexchange.com/a/91247/4999 | |
Nov 10, 2018 at 18:47 | history | edited | apt45 | CC BY-SA 4.0 |
edited body
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Nov 10, 2018 at 17:54 | comment | added | apt45 |
@HenrikSchumacher Even If I add a fictitious variable k in FindRoot with arbitrary initial value, it finds a singular Jacobian at the initial condition points. See here i63.tinypic.com/2is6omd.png . I do not why.
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Nov 10, 2018 at 17:43 | comment | added | apt45 | @HenrikSchumacher thanks for the suggestion. The point is that I have 13 equations from the system + the 2 constraints $\vec{x}.\vec{x}=1$, $\vec{y}.\vec{y}=1$ which gives 15 equations. On the contrary, I have only 14 variables. So, FindRoot complains that the numbers do not match. | |
Nov 10, 2018 at 17:32 | comment | added | Henrik Schumacher |
What about FindRoot ?
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Nov 10, 2018 at 17:24 | history | asked | apt45 | CC BY-SA 4.0 |