Revisions to Find the list that best matches reference list

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edited Feb 20, 2019 at 18:19

Suppose I have the reference list a and a matrix otherLists of all other lists I want to compare against a:

otherLists[[Ordering[LengthotherLists[[Ordering[Length[#] & /@ (Complement[a, #]&#] & /@ otherLists), 1]]]

This will return the list that best matches a.

Suppose I have the reference list a and a matrix otherLists of all other lists I want to compare against a:

otherLists[[Ordering[Length /@ (Complement[a, #]& /@ otherLists), 1]]]

This will return the list that best matches a.

Suppose I have the reference list a and a matrix otherLists of all other lists I want to compare against a:

otherLists[[Ordering[Length[#] & /@ (Complement[a, #] & /@ otherLists), 1]]]

This will return the list that best matches a.

Replaced Length[#]& with simpler Length

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edited Feb 20, 2019 at 5:07

Suppose I have the reference list a and a matrix otherLists of all other lists I want to compare against a:

otherLists[[Ordering[Length[#] &otherLists[[Ordering[Length /@ (Complement[a, #] &#]& /@ otherLists), 1]]]

This will return the list that best matches a.

Suppose I have the reference list a and a matrix otherLists of all other lists I want to compare against a:

otherLists[[Ordering[Length[#] & /@ (Complement[a, #] & /@ otherLists), 1]]]

This will return the list that best matches a.

Suppose I have the reference list a and a matrix otherLists of all other lists I want to compare against a:

otherLists[[Ordering[Length /@ (Complement[a, #]& /@ otherLists), 1]]]

This will return the list that best matches a.

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created Oct 8, 2018 at 4:39

Suppose I have the reference list a and a matrix otherLists of all other lists I want to compare against a:

otherLists[[Ordering[Length[#] & /@ (Complement[a, #] & /@ otherLists), 1]]]

This will return the list that best matches a.

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