2 The original equation simplified to 1/B. The new simplifies to 1/ (-A + B + C)

A very simple and direct question, I know. But there are, in my view, surprisingly few simple and direct answers on the net.

My question is, suppose I have the following equation $$Y = 1/(A-(A-B))$$$$Y = 1/(C-(A-B))$$ and $$B$$ is a random variable that follows the Normal distribution, say. How do I:

1: Use Mathematica to obtain the equation for $$Y$$?

2: Find the mean of the equation found in 1.

A very simple and direct question, I know. But there are, in my view, surprisingly few simple and direct answers on the net.

My question is, suppose I have the following equation $$Y = 1/(A-(A-B))$$ and $$B$$ is a random variable that follows the Normal distribution, say. How do I:

1: Use Mathematica to obtain the equation for $$Y$$?

2: Find the mean of the equation found in 1.

A very simple and direct question, I know. But there are, in my view, surprisingly few simple and direct answers on the net.

My question is, suppose I have the following equation $$Y = 1/(C-(A-B))$$ and $$B$$ is a random variable that follows the Normal distribution, say. How do I:

1: Use Mathematica to obtain the equation for $$Y$$?

2: Find the mean of the equation found in 1.

1

# Working with a random variable in an equation

A very simple and direct question, I know. But there are, in my view, surprisingly few simple and direct answers on the net.

My question is, suppose I have the following equation $$Y = 1/(A-(A-B))$$ and $$B$$ is a random variable that follows the Normal distribution, say. How do I:

1: Use Mathematica to obtain the equation for $$Y$$?

2: Find the mean of the equation found in 1.