Timeline for Creating 15x15 matrix out of two 6x6 matrices (by antisymmetrization)
Current License: CC BY-SA 4.0
6 events
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May 16, 2020 at 8:22 | history | edited | J. M.'s missing motivation♦ | CC BY-SA 4.0 |
added 16 characters in body
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Jul 10, 2018 at 16:46 | history | edited | jose | CC BY-SA 4.0 |
added 338 characters in body
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Jul 7, 2018 at 3:00 | comment | added | user195583 | I managed to understand it and edited my definition of $\Lambda^I_J$ in my original question. | |
Jul 7, 2018 at 2:21 | comment | added | user195583 | This is an "errata" to the last bit in my previous comment "The entries of the 15 $\times$15 matrix $A$ are defined in terms of the entries of the $\Lambda^I_J$ matrix (not using the entire matrix)". At this point, I'm getting a bit confused myself - I know for sure that $A$ are labeled by antisymmetric pair of indices $IM,JN$ and since these run from 1-6, $A$ should be 15D, but I'm confused on the summation part. As written above, clearly $\Lambda^1_3$ should refer to the entire $6\times 6$ matrix labeled as $\Lambda^1_3$, not any particular entry. | |
Jul 7, 2018 at 2:02 | comment | added | user195583 | Thanks for your code with the detailed explanation. I put the code in my ancient Mathematica 8, and currently I got some big error messages which I'm trying to understand - I suspect it's due to the old version. You're right - The entries of the 15 $\times$15 matrix $A$ are defined in terms of the entries of the $\Lambda^I_J$ matrix (not using the entire matrix). For example: $A_{12,34} =\Lambda^1_3 \delta^2_4$. | |
Jul 6, 2018 at 14:09 | history | answered | jose | CC BY-SA 4.0 |