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Timeline for Plotting region from list

Current License: CC BY-SA 4.0

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Jul 8, 2018 at 15:37 history tweeted twitter.com/StackMma/status/1015983215683784704
Jul 4, 2018 at 12:37 vote accept SarahThompson
Jun 28, 2018 at 11:01 comment added SarahThompson @LukasLang - That was very helpful, it does indeed do most of what I want and seems to be the best solution so far. The region boundaries are not always as smooth as I'd like, but I suppose I'll just need to scan across finer intervals.
Jun 28, 2018 at 10:57 comment added SarahThompson @DavidG.Stork - Thanks, I am definitely trying to use the functionality of RegionPlot or ListPlot directly. Your first suggestion with ListPlot3D doesn't really work as I am simply looking for a region on the (2D) x-y plane to be shaded in. While the shape of the 3D plot from ListPlot3D is encouraging, I am not sure if I need the extra dimension...any ideas how to select the last value in each subset and have a constraint on that in a RegionPlot argument? I am struggling with using RegionPlot on lists.
Jun 28, 2018 at 10:54 comment added SarahThompson @AlexeiBoulbitch - Thanks, have had a look at that. I guess in my case it would be something like Select[list, 5 < Last[#] < 7 &], although I am not sure how to pass this into a RegionPlot argument?
Jun 28, 2018 at 10:29 history edited kglr CC BY-SA 4.0
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Jun 28, 2018 at 10:19 answer added kglr timeline score: 2
Jun 27, 2018 at 19:55 comment added David G. Stork Select will allow you to select the data that obeys some constraint, but if you use RegionPlot or simple ListPlot3D, etc., you will likely get the full range of positions, not restricted to where the data lie.
Jun 27, 2018 at 19:44 comment added Alexei Boulbitch Have you seen Select?
Jun 27, 2018 at 19:35 comment added Lukas Lang I think you're looking for ListContourPlot. It accepts data in exactly your format, and you can easily specify which contours to draw using Contours (i.e. which regions).
Jun 27, 2018 at 19:33 comment added David G. Stork ListPlot3D[xxx, RegionFunction-> Function[{z}, z<5]]
Jun 27, 2018 at 19:07 history asked SarahThompson CC BY-SA 4.0