Timeline for Evaluating integral seems incorrect
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Jun 7, 2018 at 10:49 | vote | accept | CommunityBot | ||
| Jun 7, 2018 at 10:42 | vote | accept | CommunityBot | ||
| Jun 7, 2018 at 10:47 | |||||
| Jun 7, 2018 at 10:36 | answer | added | Mariusz Iwaniuk | timeline score: 4 | |
| Jun 7, 2018 at 10:29 | comment | added | user55387 | So it would be Integrate[ 1/γ^2* Exp[-t/γ - RealAbs[t - τ]/μ]*(t - t^2/(2*γ)), {t,0,Infinity}] ? | |
| Jun 7, 2018 at 10:23 | comment | added | Mariusz Iwaniuk |
It depends if function is continuous.In your case it is not.Try:Integrate[ 1/γ^2* Exp[-t/γ - RealAbs[t - τ]/μ]*(t - t^2/(2*γ)), t] and ?
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| Jun 7, 2018 at 10:18 | comment | added | user55387 | Sure, but is the same as evaluating the indefinite integral and then plugging in the limits. | |
| Jun 7, 2018 at 10:18 | comment | added | Mariusz Iwaniuk |
Not t use {t,0,Infinity} inside Integrate.
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| Jun 7, 2018 at 10:14 | history | edited | user55387 | CC BY-SA 4.0 |
deleted 16 characters in body
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| Jun 7, 2018 at 10:07 | history | edited | Mariusz Iwaniuk | CC BY-SA 4.0 |
improved formatting
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| Jun 7, 2018 at 10:02 | history | asked | user55387 | CC BY-SA 4.0 |