Timeline for How to take derivative of the argument of an interpolating function
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| May 30, 2018 at 15:19 | history | edited | MarcoB | CC BY-SA 4.0 |
Formatted code
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| May 30, 2018 at 14:31 | review | Low quality posts | |||
| May 30, 2018 at 14:36 | |||||
| May 30, 2018 at 14:31 | history | edited | Gopal Verma | CC BY-SA 4.0 |
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| May 30, 2018 at 14:23 | history | undeleted | Gopal Verma | ||
| May 30, 2018 at 14:23 | history | deleted | Gopal Verma | via Vote | |
| May 30, 2018 at 14:23 | comment | added | Gopal Verma | you can try with D[ComplexExpand[Arg[u[t, x]], TargetFunctions -> {Re, Im}], x] | |
| May 30, 2018 at 14:02 | comment | added | sudipta | Not Arg[D[u[x,t]]], I want to calculate D[Arg[u[x,t]]]. They are not same! | |
| May 30, 2018 at 13:59 | comment | added | Gopal Verma | Arg is also working. You can see the updated figure. | |
| May 30, 2018 at 13:58 | history | edited | Gopal Verma | CC BY-SA 4.0 |
deleted 51 characters in body
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| May 30, 2018 at 13:09 | comment | added | sudipta | I'm trying to find out the derivative of Arg[u], not Abs[D[u]]. They are not same. | |
| May 30, 2018 at 11:57 | history | answered | Gopal Verma | CC BY-SA 4.0 |