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Jan 20 at 5:18 comment added Y. zeng Still need a new way to calculate this in Mathematica.
Apr 11, 2018 at 17:38 vote accept mdcq
Apr 11, 2018 at 13:39 comment added Daniel Lichtblau This will give a form of parametrized solution set: xx = Array[x,2];Solve[A.xx==b,xx]
Apr 11, 2018 at 13:28 answer added Henrik Schumacher timeline score: 2
Apr 11, 2018 at 13:18 history edited J. M.'s missing motivation
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Apr 11, 2018 at 13:15 history asked mdcq CC BY-SA 3.0