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Timeline for Precision differences

Current License: CC BY-SA 3.0

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Dec 29, 2012 at 19:35 history edited Artes CC BY-SA 3.0
added an example where NSum works while Sum does not
Dec 29, 2012 at 6:33 vote accept Fred Daniel Kline
Dec 28, 2012 at 21:57 history edited Artes CC BY-SA 3.0
added 77 characters in body
Dec 28, 2012 at 20:51 history edited Artes CC BY-SA 3.0
added appropriate settings for NSum
Dec 28, 2012 at 20:07 comment added Fred Daniel Kline Sum[(1/k^2 + 1/(k^2 - k)), {k, 2, Infinity}] - Zeta[2] Here I changed the minus to a plus.
Dec 28, 2012 at 19:43 comment added Artes @FredKline Just evaluate this Sum[1/k^2, {k, Infinity}] - Zeta[2] to understand what I mean.
Dec 28, 2012 at 19:34 comment added Fred Daniel Kline I misunderstood. Change the $-$ between the two terms to a $+$ to get zeta[2].
Dec 28, 2012 at 18:59 comment added Fred Daniel Kline The second one---1/k^2 (but starting with k=1).
Dec 28, 2012 at 18:51 comment added Artes @FredKline In these both cases NSum cannot very accurately estimate the results. You should better use Sum wherever it would be possible. Which one does converge to Zeta[2] ?
Dec 28, 2012 at 18:40 comment added Fred Daniel Kline +1, because I replaced the constant one with a sum that converges to one, this might be a pathelogical example. The pronic numbers may converge to one at a different rate than zeta[2] converges.
Dec 28, 2012 at 18:21 history answered Artes CC BY-SA 3.0