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Mar 10, 2018 at 23:55 vote accept Lagiacrus
Mar 3, 2018 at 14:00 comment added kglr @Lagiacrus, you can change {0, 2, 2} in the definition of binlists to {0,, 4, 4} if the third list can take values in {0,1,2,3}.
Mar 3, 2018 at 12:57 comment added Lagiacrus So far the code appears to have been working well, but I just tried it for a similar situation in which the third element of the list can be either 0, 1, 2 or 3 (instead of the original 0 or 1) and in this case the binmeans never ends up with a value higher than 1. Is there a limit on the value that binmeans can take?
Feb 27, 2018 at 20:48 history edited kglr CC BY-SA 3.0
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Feb 27, 2018 at 20:17 comment added kglr @Lagiacrus, right; changing 5 changes the number of bins. Re ticks, please see the updated version.
Feb 27, 2018 at 20:08 history edited kglr CC BY-SA 3.0
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Feb 27, 2018 at 19:46 history edited kglr CC BY-SA 3.0
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Feb 27, 2018 at 18:38 comment added Lagiacrus I take it that if I would like to increase the number of squares, I just alter that 5 in the second line? Also, I tried changing it to 25 and it looks good, but there are a lot of data ticks. Is it possible to maybe only show every second, or even third data tick?
Feb 27, 2018 at 1:38 history edited kglr CC BY-SA 3.0
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Feb 27, 2018 at 1:29 history edited kglr CC BY-SA 3.0
deleted 19 characters in body
Feb 27, 2018 at 0:01 history answered kglr CC BY-SA 3.0