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Bumped by Community user
Routine clean-up
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m_goldberg
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Phase Portraitportrait plotting

I'm trying to plot a phase portrait for the equation:

(d^2/dt^2)y + b * (dy/dt)^2 = A, A > 0, b < 0

The first think I'm doing is justthing I did was changing dy/dt = to p[y], so the equation is:

p'[y] + b * (p[y])^2 = A, A > 0, b < 0

When i'm using StreamPlotHowever, when I make a stream plot and substitutionsubstitute for AA and bb, iI see justa blank graphplot. How is it better to implement itcan I fix this?

Phase Portrait plotting

I'm trying to plot a phase portrait for the equation:

(d^2/dt^2)y + b * (dy/dt)^2 = A, A > 0, b < 0

The first think I'm doing is just changing dy/dt = p[y], so the equation is:

p'[y] + b * (p[y])^2 = A, A > 0, b < 0

When i'm using StreamPlot and substitution for A and b, i see just blank graph. How is it better to implement it?

Phase portrait plotting

I'm trying to plot a phase portrait for the equation:

(d^2/dt^2)y + b * (dy/dt)^2 = A, A > 0, b < 0

The first thing I did was changing dy/dt to p[y], so the equation is:

p'[y] + b * (p[y])^2 = A, A > 0, b < 0

However, when I make a stream plot and substitute for A and b, I see a blank plot. How can I fix this?

Source Link

Phase Portrait plotting

I'm trying to plot a phase portrait for the equation:

(d^2/dt^2)y + b * (dy/dt)^2 = A, A > 0, b < 0

The first think I'm doing is just changing dy/dt = p[y], so the equation is:

p'[y] + b * (p[y])^2 = A, A > 0, b < 0

When i'm using StreamPlot and substitution for A and b, i see just blank graph. How is it better to implement it?