Timeline for How to get explicit result of geometric transformation? [duplicate]
Current License: CC BY-SA 3.0
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Dec 21, 2017 at 13:05 | history | closed |
Carl Woll LCarvalho Alexey Popkov Sektor Coolwater |
Duplicate of Why doesn't Normal[] work on GeometricTransformation? | |
Dec 20, 2017 at 22:52 | comment | added | Carl Woll |
You could use the function NormalizeGraphics from my answer to that question instead of Normal , although it still returns a Parallelogram object instead of a Rectangle object.
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Dec 20, 2017 at 22:39 | comment | added | M.R. | OK thanks, but it doesn't look like there was a simple solution to that one | |
Dec 20, 2017 at 22:10 | review | Close votes | |||
Dec 21, 2017 at 13:05 | |||||
Dec 20, 2017 at 21:53 | comment | added | Carl Woll | Then your question is probably a duplicate of mathematica.stackexchange.com/q/11430/45431. | |
Dec 20, 2017 at 21:47 | comment | added | M.R. | @CarlWoll Good point, I think I tried that and it may work but I'd like the result to be a Rectangle object, and I'd also like to understand why this other usage fails. | |
Dec 20, 2017 at 21:45 | comment | added | Carl Woll |
Why not use TransformedRegion[Rectangle[{0, 0}, {1, 1}], ScalingTransform[{.5, .5}, {.5, .5}]] instead?
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Dec 20, 2017 at 21:36 | history | asked | M.R. | CC BY-SA 3.0 |