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How to determine the center and radius of a circle given threesome points in 3D?

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I was wondering if anyone could give me a hand with this problem I have.

I have six points on a plane, and I am trying to determine if they form a circle or not.

I know that any three points in 2D can determine a circle as long as the three points don't all lie on the same line. The way I figured that problem was taking two points, finding the line that connects them, finding the midpoint of that segment and then finding a perpendicular like to the segment at that point. I do that with two segments and the intersection of the perpendicular lines that I find intersect at the center of the circle.

When I follow the steps for the points I have in 3D, MathematicaMathematica "gets stuck" when I ask it to find the equation of the line with the slope and the two points I give it. ( becausebecause the points have 3 coordinates and not two like in 2D).

Any help is greatly appreciated!

Thank you,

I was wondering if anyone could give me a hand with this problem I have.

I have six points on a plane and I am trying to determine if they form a circle or not.

I know that any three points in 2D can determine a circle as long as the three points don't all lie on the same line. The way I figured that problem was taking two points, finding the line that connects them, finding the midpoint of that segment and then finding a perpendicular like to the segment at that point. I do that with two segments and the intersection of the perpendicular lines that I find intersect at the center of the circle.

When I follow the steps for the points I have in 3D, Mathematica "gets stuck" when I ask it to find the equation of the line with the slope and the two points I give it. ( because the points have 3 coordinates and not two like in 2D).

Any help is greatly appreciated!

Thank you,

I was wondering if anyone could give me a hand with this problem I have.

I have six points on a plane, and I am trying to determine if they form a circle or not.

I know that any three points in 2D can determine a circle as long as the three points don't all lie on the same line. The way I figured that problem was taking two points, finding the line that connects them, finding the midpoint of that segment and then finding a perpendicular to the segment at that point. I do that with two segments and the intersection of the perpendicular lines that I find intersect at the center of the circle.

When I follow the steps for the points I have in 3D, Mathematica "gets stuck" when I ask it to find the equation of the line with the slope and the two points I give it (because the points have 3 coordinates and not two like in 2D).

Any help is greatly appreciated!

Thank you,

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