Timeline for How to obtain an unified expression for the symbolic integral?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Dec 14, 2017 at 2:03 | vote | accept | Ice0cean | ||
| Dec 12, 2017 at 11:00 | answer | added | Akku14 | timeline score: 0 | |
| Dec 12, 2017 at 9:21 | comment | added | Ice0cean |
@Mher Thanks for your comments. It works for this example. The example shown in this post is a minimal work example. I want to apply the function(The function in my real work is much complex than this example) to a large list and I found that the Limit is very time-consuming. Are there any alternative methods?
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| Dec 12, 2017 at 9:10 | comment | added | Mher |
In fact the function f(m,n) is applicable for the cases m=n, if one takes the limit n->m instead of assignment. Try enhance the definition: f[m_, m_]:=Limit[f[m, n], n -> m].
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| Dec 12, 2017 at 8:54 | history | asked | Ice0cean | CC BY-SA 3.0 |