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How todo I simplify theseexpressions with square root of the numberroots?

For example:I want

$\left\{\frac{1}{1+\sqrt{2}-\sqrt{3}},\sqrt{5-2 \sqrt{6}},\sqrt{4+\sqrt{15}}\right\}$

canto be simplifysimplified to

$\left\{\frac{1}{4} \left(2+\sqrt{2}+\sqrt{6}\right), \sqrt{3}-\sqrt{2}, \frac{1}{2} \left(\sqrt{6}+\sqrt{10}\right)\right\}$

But I can'thaven't been able to get thethat result with Mathematica.How How could I get it?

How to simplify these square root of the number?

For example:

$\left\{\frac{1}{1+\sqrt{2}-\sqrt{3}},\sqrt{5-2 \sqrt{6}},\sqrt{4+\sqrt{15}}\right\}$

can be simplify to

$\left\{\frac{1}{4} \left(2+\sqrt{2}+\sqrt{6}\right), \sqrt{3}-\sqrt{2}, \frac{1}{2} \left(\sqrt{6}+\sqrt{10}\right)\right\}$

But I can't get the result with Mathematica.How?

How do I simplify expressions with square roots?

I want

$\left\{\frac{1}{1+\sqrt{2}-\sqrt{3}},\sqrt{5-2 \sqrt{6}},\sqrt{4+\sqrt{15}}\right\}$

to be simplified to

$\left\{\frac{1}{4} \left(2+\sqrt{2}+\sqrt{6}\right), \sqrt{3}-\sqrt{2}, \frac{1}{2} \left(\sqrt{6}+\sqrt{10}\right)\right\}$

But I haven't been able to get that result with Mathematica. How could I get it?

1
source | link

How to simplify these square root of the number?

For example:

$\left\{\frac{1}{1+\sqrt{2}-\sqrt{3}},\sqrt{5-2 \sqrt{6}},\sqrt{4+\sqrt{15}}\right\}$

can be simplify to

$\left\{\frac{1}{4} \left(2+\sqrt{2}+\sqrt{6}\right), \sqrt{3}-\sqrt{2}, \frac{1}{2} \left(\sqrt{6}+\sqrt{10}\right)\right\}$

But I can't get the result with Mathematica.How?