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Feb 6, 2018 at 15:48 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jan 7, 2018 at 14:56 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Dec 8, 2017 at 13:58 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Nov 8, 2017 at 13:27 answer added Chris Degnen timeline score: 0
Nov 8, 2017 at 3:48 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Oct 12, 2017 at 11:49 comment added LLlAMnYP list2[a_] := List[]; creates a "function" named list2 which, by default, returns List[]. Your For loop then overloads list2 for a specific case where the argument is explicitly a. After running your code then typing list2[a] a result identical to typing list1[a] is returned. Note that the definitions for list2[1] or list2[someotherargument] have not been modified.
Oct 9, 2017 at 10:36 comment added aardvark2012 Or this?
Oct 9, 2017 at 3:28 comment added aardvark2012 Have you looked at this?
Oct 8, 2017 at 23:00 answer added bill s timeline score: 1
Oct 8, 2017 at 22:54 comment added RicardoP I rewrote my question to make it more clear! Thank you
Oct 8, 2017 at 22:54 history edited RicardoP CC BY-SA 3.0
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Oct 8, 2017 at 22:28 comment added bill s Your use of Append seems wrong, I think you may mean AppendTo. But honestly, I can't figure out what question you are asking. Can you pare it down to a simple version?
Oct 8, 2017 at 22:16 comment added RicardoP Concerning your other question, that is my fault! I thought I hadn't post the question, after some time of no answers and posted it again (I was getting used to this forums quick answers), but people just hadn't seen the question yet. My bad!
Oct 8, 2017 at 22:12 comment added RicardoP Sorry!I was not very clear.In the end I want to have a function which is the sum of other functions.These other functions are built using the vectors I mentioned from the list I input as the first argument and the expression inside the append. All of these are always functions of a. The auxList is the list of these functions. Later I would want to define another function which is the sum of each of auxList elements. And this last function is still a function of "a".Before defining this last function,I used auxList[1] to see if it substituted the variable "a by one but return the empty brackets
Oct 8, 2017 at 22:11 comment added aardvark2012 And how does this question differ from this one?
Oct 8, 2017 at 22:06 history edited RicardoP CC BY-SA 3.0
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Oct 8, 2017 at 21:56 comment added aardvark2012 Without more info about your argument list I can't figure out what your function is trying to do. But does With[{list = Table[i a, 5]}, Table[c1* ArcCos[(list[[i]].list[[i + 1]])/(Norm[list[[i]]]* Norm[list[[i + 1]]])], {i, Length[list] - 1}] ] output something like what you're looking for (ie: a list of functions)?
Oct 8, 2017 at 20:37 history asked RicardoP CC BY-SA 3.0