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Timeline for Using an inequality to select elements from a list and then plotting the results

Current License: CC BY-SA 3.0

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Dec 5, 2012 at 3:29 vote accept user4341
Dec 5, 2012 at 3:27 vote accept user4341
Dec 5, 2012 at 3:29
Dec 5, 2012 at 2:18 answer added kglr timeline score: 1
Dec 5, 2012 at 2:04 vote accept user4341
Dec 5, 2012 at 3:27
S Dec 5, 2012 at 1:38 history suggested m_goldberg CC BY-SA 3.0
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Dec 5, 2012 at 1:36 answer added Andy Ross timeline score: 7
Dec 5, 2012 at 1:33 review Suggested edits
S Dec 5, 2012 at 1:38
Dec 5, 2012 at 1:28 history edited m_goldberg
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Dec 5, 2012 at 1:18 comment added user4341 Right. So let's say the max value was .05, then I want to find count all values in logr that are greater than .05, and then divide how ever many numbers I found that were greater than .05 by Length[logr]. But instead of using just the max value, I want to do it for all listed values in x.
Dec 5, 2012 at 1:12 comment added cartonn If you are looking for values in logr that are greater than the max element in x (hence all elements in x), all you will find are the ones that were rounded down to the max value in x. Am I right?
Dec 5, 2012 at 1:09 comment added user4341 What I'm trying to do is find typical values of logr, which i denoted x. And then count which values of logr are greater than x. I didn't know how to find "typical values" so I tallied all of the rounded values and am going to use those.
Dec 5, 2012 at 1:02 comment added cartonn What elements of "logr" and "x" are you trying to compare? The list x already consists of elements in logr, just rounded to the nearest 0.001. Are you trying to do an element by element compare?
Dec 5, 2012 at 0:53 history asked user4341 CC BY-SA 3.0