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Sep 8, 2017 at 22:20 history tweeted twitter.com/StackMma/status/906281142915084288
Sep 8, 2017 at 15:08 answer added Mr.Wizard timeline score: 4
Sep 8, 2017 at 13:55 comment added giulio bullsaver @Szabolcs thank you! I guess this With[{mu= mu0,...] solution is the one I like best!
Sep 8, 2017 at 13:45 comment added Lukas Lang Could it be that there's an issue with the ordering of the indexes for data? Judging from m=data//Length, data seems to be a $n\times 2$ array, but later you're accessing it with i as first index, with $i\in\{1,2\}$
Sep 8, 2017 at 12:52 comment added Szabolcs Actually you should not be using Block here because the results will be messed up if data contains \[Mu] (or even i). Generally, stick to Module unless you know that you need Block. If you use Module, you will need separate mu and mu0 due to Module's symbol renaming.
Sep 8, 2017 at 12:47 comment added Szabolcs Re your update: Once you've calculated $\mu$ and $\sigma$ and stored them into mu0 and sigma0, use With to inject them. With[{mu = mu0, sigma = sigma0}, Function[..., ... mu ... sigma ...]]. In fact you can even just use mu and sigma throughout (not mu0) and do With[{mu=mu, sigma=sigma}, ...]. If this is confusing to you, stick to separate names (mu and mu0).
Sep 8, 2017 at 12:43 comment added Szabolcs Why do you keep using Return and extra semicolons when they are not necessary (even even hurt performance)? Use Block[{}, ...; result], not Block[{}, ...; x = result; Return[x];].
Sep 8, 2017 at 12:19 history edited giulio bullsaver CC BY-SA 3.0
reformulate the problem
Sep 8, 2017 at 11:47 answer added Szabolcs timeline score: 9
Sep 8, 2017 at 11:47 answer added Lukas Lang timeline score: 5
Sep 8, 2017 at 11:45 history edited giulio bullsaver CC BY-SA 3.0
typos
Sep 8, 2017 at 11:45 comment added giulio bullsaver Sorry, I misswrote the code, now is correct.
Sep 8, 2017 at 11:41 review First posts
Sep 8, 2017 at 11:47
Sep 8, 2017 at 11:38 history asked giulio bullsaver CC BY-SA 3.0