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Sep 2, 2017 at 13:09 history tweeted twitter.com/StackMma/status/903968043415588864
Aug 23, 2017 at 3:31 comment added JimB Given the example you've added, you should consider taking the logs of the bin boundaries and see mathematica.stackexchange.com/questions/35588/… for a visual display.
Aug 22, 2017 at 21:28 comment added JimB Because all of the data is binned, it's completely censored and not just because the rightmost interval is open.
Aug 22, 2017 at 21:19 history edited astrsk CC BY-SA 3.0
supplied data
Aug 22, 2017 at 17:26 answer added JimB timeline score: 4
Aug 22, 2017 at 11:18 answer added Szabolcs timeline score: 4
Aug 22, 2017 at 10:20 comment added Szabolcs Alternatively, you can apply HistogramDistribution to a WeightedData object to do this in a fully documented way.
Aug 22, 2017 at 10:16 comment added Szabolcs Here's how to create a HistogramDistribution from already binned data.
Aug 22, 2017 at 1:10 answer added Edmund timeline score: 6
Aug 18, 2017 at 19:45 comment added astrsk we do not have any pre-set distribution. Just counted hist. data, from which I infer some distribution. A particular problem is comparing data with, e.g., normal dist (null hypothesis that data come from it). But the first step is to build density distribution (bins are unequal, but distributed close to logarithm, like: 200-300-500-1000-2000-3000- >3000). So it is to build true density hist. adjusting bar heights, and then via kernel smoothing infer a nonparametric estimation of the distribution. HistogramDistribution seems to do this for raw data, the same is for SmoothKernelDistribution
Aug 18, 2017 at 17:34 comment added JimB Do you have a specific distribution in mind? Or is this just for any general histogram without a specific distribution in mind? I ask because if one has the histogram (counts and bin structure) and that the distribution is, say, a normal distribution, then there is an approach to obtain maximum likelihood estimates of the two parameters (mean and standard deviation in this case) that is very different than pretending a uniform distribution within a bin.
Aug 18, 2017 at 17:03 history edited m_goldberg CC BY-SA 3.0
Made English more idiomatic
Aug 18, 2017 at 16:35 comment added J. M.'s missing motivation Have you seen HistogramDistribution[] and SmoothKernelDistribution[]?
Aug 18, 2017 at 16:29 history asked astrsk CC BY-SA 3.0