Timeline for Making Replace or "/." stop after first replacement [duplicate]
Current License: CC BY-SA 3.0
8 events
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| May 7, 2017 at 9:33 | comment | added | Gaby Fleurov | Thanks for all the answers! I'll try them out, @mikado, the question indicated was exactly what I was looking for, probably I haven't been clear enough. | |
| May 5, 2017 at 20:18 | comment | added | mikado | I'm not sure that this is a duplicate of the question indicated. If it isn't, I suggest editing the question to give 1) an example input 2) an example set of rules and 3) the output desired. | |
| May 5, 2017 at 19:22 | comment | added | andre314 |
In some cases ReplaceList[exp,rule,1]can do the job. The problem is that the rule is only applied at level 0 of exp. Example : to replace 1 by 2 only one time in {1,1,1}, do ReplaceList[{1,1,1},{a___,1,b___}:> {a,2,b},1]. Result : {{2, 1, 1}}
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| May 5, 2017 at 18:58 | history | closed |
Jason B. CommunityBot |
Duplicate of How to replace the first occurence in an expression instead of replacing all? | |
| May 5, 2017 at 18:53 | comment | added | Jason B. |
Or, much more hacky, replacement = "A"; {"a", "b", "a", "c"} /. x : "a" :> With[{res = replacement}, replacement = x; res]
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| May 5, 2017 at 18:51 | comment | added | Bob Hanlon |
replaceFirst[expr_, old_, new_] := ReplacePart[expr, Position[expr, old][[1]] -> new]
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| May 5, 2017 at 18:37 | review | First posts | |||
| May 5, 2017 at 18:39 | |||||
| May 5, 2017 at 18:32 | history | asked | Gaby Fleurov | CC BY-SA 3.0 |