Timeline for Removing variable characters from set of solutions
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Apr 5, 2017 at 17:16 | comment | added | Cuhrazatee | @ J.M. How did you get the text to look like Mathematica code? | |
| Apr 5, 2017 at 17:15 | vote | accept | Cuhrazatee | ||
| Apr 5, 2017 at 17:13 | vote | accept | Cuhrazatee | ||
| Apr 5, 2017 at 17:15 | |||||
| Apr 5, 2017 at 10:46 | comment | added | corey979 |
For fun - pattern matching: Roots[-z^4 + 6 z^2 - 1 == 0, z] /. Equal[a_, b_] :> b.
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| Apr 5, 2017 at 1:38 | history | edited | J. M.'s missing motivation♦ |
edited tags
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| Apr 5, 2017 at 1:38 | comment | added | J. M.'s missing motivation♦ |
You're working too hard: fz = z/(-z^4 + 6 z^2 - 1); Table[Residue[fz, {z, res}], {res, z /. Solve[Denominator[fz] == 0, z]}]. Replace Table[] with Sum[] if you're doing contour integration.
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| Apr 5, 2017 at 1:36 | answer | added | Edmund | timeline score: 2 | |
| Apr 5, 2017 at 1:35 | comment | added | user46676 |
Try {Map[Last, Roots[-z^4 + 6 z^2 - 1 == 0, z]]}
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| Apr 5, 2017 at 1:29 | history | edited | David G. Stork | CC BY-SA 3.0 |
deleted 129 characters in body
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| Apr 5, 2017 at 1:18 | history | edited | Cuhrazatee | CC BY-SA 3.0 |
edited title
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| Apr 5, 2017 at 1:03 | review | First posts | |||
| Apr 5, 2017 at 2:41 | |||||
| Apr 5, 2017 at 1:02 | history | asked | Cuhrazatee | CC BY-SA 3.0 |