Timeline for Numbering element in descending order
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Oct 30, 2012 at 14:02 | comment | added | Oleksandr R. |
Two or more, use a... Nest? Dijkstra would be proud! :)
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| Oct 30, 2012 at 12:37 | comment | added | Dr. belisarius |
@J.M. orderingBy[list_, f_] := Ordering[{f@#, #} & /@ list]
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| Oct 30, 2012 at 11:48 | comment | added | Mr.Wizard | @SungjinLee take a look at this: mathematica.stackexchange.com/q/2934/121 | |
| Oct 30, 2012 at 11:14 | comment | added | J. M.'s missing motivation♦ |
@Sungjin, Ordering[{{1, 5}, {2, 8}, {3, 9}, {4, 2}, {5, 9}, {6, 7}, {7, 9}, {8, 10}, {9, 5}, {10, 2}}, All, If[Last[#1] != Last[#2], Last[#1] > Last[#2], First[#1] <= First[#2]] &]
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| Oct 30, 2012 at 11:07 | comment | added | J. M.'s missing motivation♦ |
Sometimes, I wish they'd added an OrderingBy[] in complete analogy to SortBy[]...
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| Oct 30, 2012 at 11:02 | comment | added | Sungjin Lee | oh, I miss that part. If second element is same, I want to rank the sublists in ascending order of first element. Can you help me one more time please? | |
| Oct 30, 2012 at 10:59 | history | edited | Mr.Wizard | CC BY-SA 3.0 |
added 158 characters in body
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| Oct 30, 2012 at 10:50 | history | answered | Mr.Wizard | CC BY-SA 3.0 |