Timeline for FindCurvePath for lines (rather than points)
Current License: CC BY-SA 3.0
11 events
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| Jun 16, 2020 at 9:23 | history | edited | CommunityBot |
Commonmark migration
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| Feb 19, 2017 at 3:40 | history | edited | yode | CC BY-SA 3.0 |
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| Feb 18, 2017 at 14:09 | history | edited | yode | CC BY-SA 3.0 |
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| Feb 18, 2017 at 12:54 | history | edited | yode | CC BY-SA 3.0 |
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| Feb 16, 2017 at 8:31 | comment | added | Mr.Wizard | Yes, the idea is to complete a single continuous line but there is no expectation that it forms a closed circuit. However I welcome a fast solution that does either, i.e. beats the performance of Simon Woods's answer in either form. | |
| Feb 16, 2017 at 8:19 | comment | added | yode | @Mr.Wizard In your gap case,do you wanna leave the maximal gap as your self-answer or whatever it is? | |
| Feb 16, 2017 at 6:24 | comment | added | Mr.Wizard |
You mean my self-answer? It does work on the case with gaps as I showed. As noted in the question I also need to allow for gaps between lines. End points will not always be as close as in this example. Nevertheless I will vote for your answer for showing me RelationGraph.
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| Feb 16, 2017 at 2:57 | comment | added | yode | @Mr.Wizard But your this post is about no gap case or I misunderstand? | |
| Feb 16, 2017 at 2:01 | comment | added | yode | @Mr.Wizard Yes,It cannot. | |
| Feb 16, 2017 at 1:38 | comment | added | Mr.Wizard |
It seems I do not have RelationGraph in Mathematica 10.1. Based on the appearance of IntersectingQ I am guessing that this code does not handle the case with gaps, dat2, correct?
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| Feb 15, 2017 at 17:39 | history | answered | yode | CC BY-SA 3.0 |