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Feb 6, 2017 at 10:39 history closed bbgodfrey
MarcoB
m_goldberg
C. E.
corey979
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Feb 6, 2017 at 8:57 vote accept Ehsan F
Feb 6, 2017 at 8:31 history edited m_goldberg CC BY-SA 3.0
Routine clean-up
Feb 6, 2017 at 7:42 answer added m_goldberg timeline score: 6
Feb 6, 2017 at 7:40 review Close votes
Feb 6, 2017 at 10:39
Feb 6, 2017 at 7:40 comment added MarcoB @EhsanF Your sets are still of different length; y2 is too short by one. Also, lists are enclosed by curly brances in MMA, e.g. x = {1, 2, 3, 4, 5, 6, 7, 8}. Try ListLinePlot@Transpose@{x1, y1}.
Feb 6, 2017 at 7:40 history edited Ehsan F CC BY-SA 3.0
added 1 character in body
Feb 6, 2017 at 7:36 comment added Ehsan F @MarcoB how plot this?x=[1,2,3,4,5,6,7,8] and y(1)=[0,11,12,13,14,15,16,17] and y(2)=[0,10,11.5,12.5.13.5,14.5,15.2,16] and a vertical line at x=12
Feb 6, 2017 at 7:31 comment added Ehsan F @MarcoB no i can do my work by equal length data
Feb 6, 2017 at 7:05 review Low quality posts
Feb 6, 2017 at 8:36
Feb 6, 2017 at 6:57 history edited MarcoB CC BY-SA 3.0
Removed duplicate text
Feb 6, 2017 at 6:56 comment added Nasser Your data is inconsistent. You have 9 x values, and only 8 y1 values. I can't read y2. Any way, check ListLinePlot and check Show to combine. And check Line to make line.
Feb 6, 2017 at 6:55 comment added MarcoB Would you please present your data in Mathematica format, i.e. as a list delimited by curly braces { }? Normally, Transpose@{x,y1} would give you a dataset you could plot using ListPlot, as was pointed out to you in your previous question. However, your data sets have different lengths, so that wouldn't work. Do you really have to deal with different-length lists?
Feb 6, 2017 at 6:47 history asked Ehsan F CC BY-SA 3.0