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Mr.Wizard
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Mr.Wizard
  • 273.1k
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I have an question about solving equation.

x and y are variable, and a, b, and c are complex constant.

The equations is formed like  : x^2/a - y^2/b = c$x^2/a - y^2/b = c$.

I want to contour plot a graph range from x1 < Re(x) < x2$x1 < Re(x) < x2$ to y1 < Re(y) < y2$y1 < Re(y) < y2$. x1$x1$, x2$x2$, y1$y1$, and y2$y2$ is real number even though x$x$ and y$y$ satisfied this equation are complex number.

I have used ContourPlot[x^2/a - y^2/b == c, {x, x1, x2}, {y, y1, y2}].

ContourPlot[x^2/a - y^2/b == c, {x, x1, x2}, {y, y1, y2}]

However, because this considers only real case, I can't find a solution.

If anyone has a idea, please help me.

Thank you.

I have an question about solving equation.

x and y are variable, and a, b, and c are complex constant.

The equations is formed like  : x^2/a - y^2/b = c.

I want to contour plot a graph range from x1 < Re(x) < x2 to y1 < Re(y) < y2. x1, x2, y1, and y2 is real number even though x and y satisfied this equation are complex number.

I have used ContourPlot[x^2/a - y^2/b == c, {x, x1, x2}, {y, y1, y2}]. However, because this considers only real case, I can't find a solution.

If anyone has a idea, please help me.

Thank you.

I have an question about solving equation.

x and y are variable, and a, b, and c are complex constant.

The equations is formed like: $x^2/a - y^2/b = c$.

I want to contour plot a graph range from $x1 < Re(x) < x2$ to $y1 < Re(y) < y2$. $x1$, $x2$, $y1$, and $y2$ is real number even though $x$ and $y$ satisfied this equation are complex number.

I have used

ContourPlot[x^2/a - y^2/b == c, {x, x1, x2}, {y, y1, y2}]

However, because this considers only real case, I can't find a solution.

If anyone has a idea, please help me.

Thank you.

Source Link

How can I find solution and plot multi complex variable equation?

I have an question about solving equation.

x and y are variable, and a, b, and c are complex constant.

The equations is formed like : x^2/a - y^2/b = c.

I want to contour plot a graph range from x1 < Re(x) < x2 to y1 < Re(y) < y2. x1, x2, y1, and y2 is real number even though x and y satisfied this equation are complex number.

I have used ContourPlot[x^2/a - y^2/b == c, {x, x1, x2}, {y, y1, y2}]. However, because this considers only real case, I can't find a solution.

If anyone has a idea, please help me.

Thank you.