Timeline for Solve $1/a - \sin(1/a)$ [duplicate]
Current License: CC BY-SA 3.0
13 events
when toggle format | what | by | license | comment | |
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Jan 22, 2017 at 10:29 | history | closed |
corey979 MarcoB m_goldberg Mr.Wizard |
Duplicate of Can Reduce *really* not solve for x here? | |
Jan 21, 2017 at 22:00 | vote | accept | Wojciech Wróblewski | ||
Jan 21, 2017 at 21:47 | comment | added | Wojciech Wróblewski | @mattiav27 n is a non-negative integer, b is given and b<a, both non-negative | |
Jan 21, 2017 at 21:13 | review | Close votes | |||
Jan 22, 2017 at 10:29 | |||||
Jan 21, 2017 at 21:02 | answer | added | Simon Woods | timeline score: 1 | |
S Jan 21, 2017 at 20:57 | history | suggested | zhk | CC BY-SA 3.0 |
syntax issue
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Jan 21, 2017 at 20:48 | answer | added | zhk | timeline score: 2 | |
Jan 21, 2017 at 20:37 | comment | added | bbgodfrey |
This problem is equivalent to Solve[Sin[x] == x, x] , which has only one solution. FindInstance[Sin[x] == x, x] gives it, {{x -> 0}} .
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Jan 21, 2017 at 20:25 | comment | added | cyrille.piatecki | Obviously this system cannot be solved analyticaly. It's not a MA problem. The solution can be found numericaly only. | |
Jan 21, 2017 at 20:19 | review | Suggested edits | |||
S Jan 21, 2017 at 20:57 | |||||
Jan 21, 2017 at 19:28 | comment | added | mattiav27 |
Are there any assumptions for n and b ? I guess that n is a non-negative integer, but b ?
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Jan 21, 2017 at 19:18 | review | First posts | |||
Jan 21, 2017 at 20:19 | |||||
Jan 21, 2017 at 19:16 | history | asked | Wojciech Wróblewski | CC BY-SA 3.0 |