Timeline for Differentiate w.r.t. squared variable
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 19, 2017 at 13:51 | vote | accept | Janosh | ||
| Jan 18, 2017 at 19:16 | history | edited | J. M.'s missing motivation♦ |
edited tags
|
|
| Jan 18, 2017 at 18:30 | history | tweeted | twitter.com/StackMma/status/821786932602617857 | ||
| Jan 18, 2017 at 18:17 | comment | added | JKreft | By the chain rule, using implicit differentiation, Df/Dx^2 = (Df/Dx) / (Dx^2/Dx), so this method would also work in general. | |
| Jan 18, 2017 at 18:13 | answer | added | chuy | timeline score: 7 | |
| Jan 18, 2017 at 17:16 | comment | added | anderstood | @swish I guess this should be an (if not the) answer. | |
| Jan 18, 2017 at 16:53 | answer | added | Felix | timeline score: 10 | |
| Jan 18, 2017 at 16:47 | comment | added | swish |
So, just D[x^4 + 2 x^2 + 6, x] / D[x^2,x]?
|
|
| Jan 18, 2017 at 16:40 | comment | added | Janosh | @anderstood $\frac{3}{2} x$. | |
| Jan 18, 2017 at 16:36 | comment | added | anderstood | What would be the derivative of $x^3$ wrt $x^2$? | |
| Jan 18, 2017 at 16:31 | history | asked | Janosh | CC BY-SA 3.0 |