Timeline for Help with simulating a system model (inverted pendulum)
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Dec 15, 2016 at 11:08 | vote | accept | Youssef Hafez | ||
| Dec 15, 2016 at 10:57 | vote | accept | Youssef Hafez | ||
| Dec 15, 2016 at 11:08 | |||||
| Dec 12, 2016 at 16:16 | answer | added | Suba Thomas | timeline score: 2 | |
| Dec 12, 2016 at 15:11 | comment | added | Phab | ok, i read the example: "to regulate an inverted pendulum about the upright position", so it should be stabilized at θ = 0 at any time. If you want to stabilize the pendulum at θ = π/6, you can't stabilize the position x=1. You would drive the car with constant speed in one direction (x grows). | |
| Dec 12, 2016 at 14:50 | comment | added | Phab | Just pass it as the input at the OutputResponse. Instead of {0,UnitStep[t] - UnitStep[t - 1]} pass {0,1}. | |
| Dec 12, 2016 at 10:08 | comment | added | LouisB |
I believe it is possible to stabilize at 30°, because one of the model inputs is the force d[t] applied at right angles to the pendulum. Expect d[t] to swing negative when $\theta$ is positive. Also, the system model has outputs $\{\theta [t], x[t]\}$ in that order, so the blue curve is $\theta$ and the red one is $x$, if I'm not mistaken.
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| Dec 12, 2016 at 3:09 | history | edited | J. M.'s missing motivation♦ |
edited tags
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| Dec 12, 2016 at 2:48 | comment | added | m_goldberg | Is it even possible for this model to stabilize with the pendulum 30° from vertical? | |
| Dec 12, 2016 at 2:41 | history | edited | m_goldberg | CC BY-SA 3.0 |
Improved formatting; added link to the relevant documentation article; inserted better plot image
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| Dec 12, 2016 at 1:54 | history | edited | m_goldberg | CC BY-SA 3.0 |
Improved formatting; added link to the relevant documentation article
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| Dec 11, 2016 at 19:09 | review | First posts | |||
| Dec 11, 2016 at 19:21 | |||||
| Dec 11, 2016 at 19:05 | history | asked | Youssef Hafez | CC BY-SA 3.0 |