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Timeline for List structure transformation

Current License: CC BY-SA 3.0

21 events
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Jan 26 at 4:44 answer added Syed timeline score: 0
Jan 26 at 1:57 answer added E. Chan-López timeline score: 1
Jan 26 at 0:15 answer added eldo timeline score: 1
Nov 15, 2016 at 13:18 vote accept Αλέξανδρος Ζεγγ
Nov 15, 2016 at 13:18 vote accept Αλέξανδρος Ζεγγ
Nov 15, 2016 at 13:18
Nov 15, 2016 at 13:18 vote accept Αλέξανδρος Ζεγγ
Nov 15, 2016 at 13:18
Nov 13, 2016 at 22:01 answer added Michael E2 timeline score: 2
Nov 13, 2016 at 20:34 answer added corey979 timeline score: 1
Nov 13, 2016 at 17:00 answer added kglr timeline score: 7
Nov 13, 2016 at 16:43 answer added m_goldberg timeline score: 2
Nov 13, 2016 at 15:40 answer added Mike Colacino timeline score: 2
Nov 13, 2016 at 11:32 review Close votes
Nov 13, 2016 at 16:43
Nov 13, 2016 at 11:31 answer added Jose Enrique Calderon timeline score: 5
Nov 13, 2016 at 11:21 comment added ubpdqn @Feyre I guess it depends on aim and exact input...both work :)
Nov 13, 2016 at 11:19 comment added Feyre @ubpdqn I was sure Join[] was going to be quicker, turns out I was wrong :/. Your first comment is the most efficient of all of these.
Nov 13, 2016 at 11:17 comment added ubpdqn just because I like Reap/Sow: Last@Reap[Sow @@ {{x, y}, {a, b, c, d, e}}, _, Append[#2[[1]], #1] &]
Nov 13, 2016 at 11:14 comment added Feyre Join[p, {#}] & /@ q
Nov 13, 2016 at 11:11 comment added Marius Ladegård Meyer First[Outer[Flatten@*List, {#1}, #2, 1, 2] & @@ {{x, y}, {a, b, c, d, e}}]
Nov 13, 2016 at 11:11 comment added corey979 Outer[Join, {p}, Partition[q, 1], 1, 1][[1]]
Nov 13, 2016 at 11:06 comment added ubpdqn {p, q} = {{x, y}, {a, b, c, d, e}}; Append[p, #] & /@ q
Nov 13, 2016 at 10:54 history asked Αλέξανδρος Ζεγγ CC BY-SA 3.0