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Feb 4, 2017 at 11:36 history edited LCarvalho CC BY-SA 3.0
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Nov 5, 2016 at 21:32 vote accept unvarnished
Oct 26, 2016 at 15:15 history tweeted twitter.com/StackMma/status/791297104807329792
Oct 26, 2016 at 13:26 answer added user21 timeline score: 5
Oct 25, 2016 at 21:00 comment added unvarnished The thing is, I really need to have access to the coordinates of the points at the surface. I will move them vertically up and down, depending on the result given by the Laplace equation, and the motion of each point has to be completely independent from the other points. The goal of the code is to reproduce ripples in the liquid. I do not understand how can MeshRefinementFunction help me with that. I do not need, for the moment, to refine the triangular mesh that I am using.
Oct 25, 2016 at 19:58 comment added tsuresuregusa I would try to rewrite it using the MeshRefinementFunction as the sum of two functions, one for the edge and other for the disk.
Oct 25, 2016 at 19:40 history edited unvarnished CC BY-SA 3.0
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Oct 25, 2016 at 19:09 history edited unvarnished CC BY-SA 3.0
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Oct 25, 2016 at 19:05 comment added unvarnished That is exactly what I want. I totally agree that it is much easier to model the circle with an actual circle! I just could not find a way to merge a boundary mesh (the surface) with a boundary created using ImplicitRegion, in order to create one single region. And I do not want to change the surface boundary mesh.
Oct 25, 2016 at 18:03 comment added tsuresuregusa you mean something like NeumannValue[f[r,z], r^2 + (z-zBallCentre)^2 ==0.5]? where f[r,z] is your velocity? Btw, you could write your code in much simpler way with regions, you don't need to specify the coordinates one by one as you do now.
Oct 25, 2016 at 15:38 history edited unvarnished CC BY-SA 3.0
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Oct 25, 2016 at 15:28 history edited unvarnished CC BY-SA 3.0
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Oct 25, 2016 at 15:20 history asked unvarnished CC BY-SA 3.0