Timeline for Finding unit tangent for a given r(t)
Current License: CC BY-SA 3.0
11 events
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| Oct 16, 2016 at 21:22 | history | edited | LCarvalho | CC BY-SA 3.0 |
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| Oct 16, 2016 at 18:24 | comment | added | krourou2 | @Artes This is not a duplicate of the linked question. I tried the solution presented, and the results were confusing; I needed a different way of going about it. The difference in the equations is probably the reason why Mathematica had been giving me difficulties with your proposed solution. | |
| Oct 7, 2016 at 9:04 | comment | added | Artes | Is it only closely related Finding unit tangent, normal, and binormal vectors for a given r(t) or simply a duplicate? If not try to explain why? | |
| Oct 7, 2016 at 2:48 | comment | added | krourou2 | ... Wow. Oh wow, that's beautiful. Thank you so much. | |
| Oct 7, 2016 at 2:33 | answer | added | Jens | timeline score: 1 | |
| Oct 7, 2016 at 2:19 | comment | added | J. M.'s missing motivation♦ |
I mean, you should use something similar to get your tangent vector, too: Simplify[r'[t]/Sqrt[r'[t].r'[t]]]. Make sure to clear all variables before trying all of these.
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| Oct 7, 2016 at 2:17 | comment | added | krourou2 |
It helped... some. Insofar as it reduced it to a two-line mess of fractions full of Abs.
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| Oct 7, 2016 at 2:11 | comment | added | J. M.'s missing motivation♦ |
Probably better off avoiding Norm[] altogether: Simplify[T'[t]/Sqrt[T'[t].T'[t]]]. You might be interested in looking at FrenetSerretSystem[], too.
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| Oct 7, 2016 at 2:09 | review | First posts | |||
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| Oct 7, 2016 at 2:06 | history | edited | J. M.'s missing motivation♦ |
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| Oct 7, 2016 at 2:04 | history | asked | krourou2 | CC BY-SA 3.0 |