Timeline for Problem storing $x_j$ terms in variable x [duplicate]
Current License: CC BY-SA 3.0
9 events
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Sep 25, 2016 at 13:10 | comment | added | Mr.Wizard | Closely related: (22376). Also perhaps worth reading, including the various questions linked therein: (6511) | |
Sep 25, 2016 at 13:01 | history | closed | Mr.Wizard | Duplicate of Recursion problem | |
Jun 24, 2016 at 20:03 | vote | accept | David | ||
Jun 23, 2016 at 22:53 | answer | added | Jason B. | timeline score: 2 | |
Jun 23, 2016 at 21:33 | comment | added | David | @J.M. Can you please give me a complete line of code for the Indexed command, storing the answer in a variable, so I am sure of what you are suggesting? Thanks. | |
Jun 23, 2016 at 20:29 | comment | added | Marius Ladegård Meyer |
Indexed or simply x[i] for the win.
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Jun 23, 2016 at 19:55 | comment | added | march |
Or do xs = Array[x, 100] , which is how I would do it. If you insist on Subscript s, do xs = Array[Subscript[x,#]&, 100]
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Jun 23, 2016 at 19:22 | comment | added | J. M.'s missing motivation♦ |
You are defining x in terms of x ; hence the error. Use Indexed[] instead.
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Jun 23, 2016 at 19:21 | history | asked | David | CC BY-SA 3.0 |