Timeline for Integrate on a contour in the complex plane
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Apr 24 at 9:09 | comment | added | Wjx |
@xzczd If it's complex path integral then it shouldn't have the Abs, I thought the question was about integral of a real value over a curve, which requires a Abs.
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| Apr 24 at 9:07 | history | edited | Wjx | CC BY-SA 4.0 |
deleted 4 characters in body
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| Apr 17 at 8:29 | comment | added | xzczd♦ |
Why do you have a Abs there? Which definition are you following?
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| Jun 7, 2016 at 0:09 | comment | added | Wjx | yeah，this code can be used in different situations, but you will need to change the function of the integration curve and the integration range. | |
| Jun 6, 2016 at 18:22 | vote | accept | Geoffrey Critzer | ||
| Jun 6, 2016 at 18:21 | comment | added | Geoffrey Critzer | OK Thanks. The result I am after is 8*Pi*I. I can use your code but the definition of complex integration is different from what you have. Also in order to integrate around the entire circle t must go from 0 to 2*Pi. z=2 Exp[I t]; f[z_]:=z+Conjugate[z]; Integrate[f[z] D[z,t],{t,0,2*Pi}] | |
| Jun 6, 2016 at 11:58 | comment | added | Wjx | If on a contour, this problem can be quite difficult as not all the time the contour can be explicitly explained by functions. But I suppose your need is just what I've posted~:) | |
| Jun 6, 2016 at 11:51 | history | edited | N.J.Evans | CC BY-SA 3.0 |
Added code formatting
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| Jun 6, 2016 at 10:58 | history | answered | Wjx | CC BY-SA 3.0 |