Timeline for Inscribed square problem
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
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| Jun 6, 2016 at 15:23 | history | edited | BlacKow | CC BY-SA 3.0 |
spelling etc
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| Jun 6, 2016 at 9:41 | vote | accept | vito | ||
| Jun 4, 2016 at 6:56 | comment | added | J. M.'s missing motivation♦ | It's cheating, but I'm fine with that. ;) Sorry I cannot give a second upvote. | |
| Jun 3, 2016 at 22:00 | history | edited | BlacKow | CC BY-SA 3.0 |
deleted 43 characters in body
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| Jun 3, 2016 at 21:56 | comment | added | BlacKow | @J.M. Just added second "obvious" square... required a bit of cheating | |
| Jun 3, 2016 at 21:49 | history | edited | BlacKow | CC BY-SA 3.0 |
two inscribed squares
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| Jun 1, 2016 at 18:01 | vote | accept | vito | ||
| Jun 3, 2016 at 9:34 | |||||
| Jun 1, 2016 at 17:23 | comment | added | J. M.'s missing motivation♦ | Yes, the part after your "not sure" was what I was thinking about; I can see how difficult it might be to do. | |
| Jun 1, 2016 at 17:15 | comment | added | BlacKow |
It's obvious that it's the only one that has the same symmetry as the curve itself... Not sure how to try to find an arbitrary tilted one. The brute force of finding four $t$ in FindRoot wouldn't work probably.
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| Jun 1, 2016 at 17:12 | comment | added | J. M.'s missing motivation♦ | On another note: this finds only one square. I wonder how difficult it would be to prove or disprove that it is the only such square for this curve? | |
| Jun 1, 2016 at 17:08 | comment | added | BlacKow | @J.M. Thanks! Never knew it exists... | |
| Jun 1, 2016 at 17:05 | comment | added | J. M.'s missing motivation♦ |
You can do maxXt = ArgMax[r[t] Cos[t], t] instead.
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| Jun 1, 2016 at 16:37 | history | edited | BlacKow | CC BY-SA 3.0 |
added 24 characters in body
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| Jun 1, 2016 at 16:27 | history | answered | BlacKow | CC BY-SA 3.0 |