Timeline for Collect/Factor a fraction
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Apr 7, 2016 at 14:13 | comment | added | Physics_maths | The code is even better now! | |
| Apr 7, 2016 at 10:27 | history | edited | Jason B. | CC BY-SA 3.0 |
added 470 characters in body
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| Apr 6, 2016 at 15:25 | comment | added | Physics_maths | OK thanks a lot for all the effort. | |
| Apr 6, 2016 at 15:25 | comment | added | Jason B. | will work on it, gotta leave for the day now though | |
| Apr 6, 2016 at 15:24 | comment | added | Physics_maths | It would be nice if your code somehow differentiated between a variable name and a number such as 2. So that c/(2b)+1/b would read (c+2)/(2b). | |
| Apr 6, 2016 at 15:23 | comment | added | Jason B. |
Can you give an example? fractionExpand[2/(1*b) + 2/c + 3/(2 b) + 4/(a b)] seems to work
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| Apr 6, 2016 at 15:17 | comment | added | Physics_maths | Now that I've played around with your code I notice that terms like 1/(2*b) and 1/(1*b) does not get written together. Your solution still answers the original question but perhaps I should've asked a more general question. Is there a simple way to fix this problem? | |
| Apr 6, 2016 at 13:05 | vote | accept | Physics_maths | ||
| Apr 6, 2016 at 13:04 | comment | added | Physics_maths | Wow, that was neat! | |
| Apr 6, 2016 at 12:16 | history | edited | Jason B. | CC BY-SA 3.0 |
added 944 characters in body
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| Apr 6, 2016 at 11:57 | history | answered | Jason B. | CC BY-SA 3.0 |