Timeline for Calling Integrate with many limits of integration
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Mar 29, 2016 at 7:15 | comment | added | J. M.'s missing motivation♦ |
Yes, Residue[] would be the more readable procedure (and SeriesCoefficient[] the most convenient); since you were asking about Integrate[], I brought out one of my usual examples. This is another one.
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| Mar 29, 2016 at 7:09 | comment | added | tparker |
Also, your example doesn't really need a specified contour at all - you can just do Table[Residue[z^-n/(1 - z - z^2), {z, 0}], {n, 5}] :)
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| Mar 29, 2016 at 7:03 | comment | added | tparker | Good eye - that's an extremely not-very-prominent spot ... | |
| Mar 29, 2016 at 7:02 | vote | accept | tparker | ||
| Mar 29, 2016 at 6:54 | history | answered | J. M.'s missing motivation♦ | CC BY-SA 3.0 |