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Antialiasing -> False will do it, which surprisingly can be used in-line as a directive:

Graphics[{Antialiasing -> False, Polygon[{{0, 0}, {1, 0}, {0, 1}}], 
  Polygon[{{1, 0}, {0, 1}, {1, 1}}]}]

Because the multiple-polygon form of Polygon (presently?) renders without antialiasing by default this also works:

Graphics[{Polygon[{{{0, 0}, {1, 0}, {0, 1}}, {{1, 0}, {0, 1}, {1, 1}}}]}]

Reference:

Antialiasing -> False will do it, which surprisingly can be used in-line as a directive:

Graphics[{Antialiasing -> False, Polygon[{{0, 0}, {1, 0}, {0, 1}}], 
  Polygon[{{1, 0}, {0, 1}, {1, 1}}]}]

Because the multiple-polygon form of Polygon (presently?) renders without antialiasing by default this also works:

Graphics[{Polygon[{{{0, 0}, {1, 0}, {0, 1}}, {{1, 0}, {0, 1}, {1, 1}}}]}]

Reference:

Antialiasing -> False will do it, which surprisingly can be used in-line as a directive:

Graphics[{Antialiasing -> False, Polygon[{{0, 0}, {1, 0}, {0, 1}}], 
  Polygon[{{1, 0}, {0, 1}, {1, 1}}]}]

Because the multiple-polygon form of Polygon (presently?) renders without antialiasing by default this also works:

Graphics[{Polygon[{{{0, 0}, {1, 0}, {0, 1}}, {{1, 0}, {0, 1}, {1, 1}}}]}]

Reference:

added 11 characters in body
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Mr.Wizard
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Antialiasing -> False will do it, which surprisingly can be used in-line as a directive:

Graphics[{Antialiasing -> False, Polygon[{{0, 0}, {1, 0}, {0, 1}}], 
  Polygon[{{1, 0}, {0, 1}, {1, 1}}]}]

Because the multiple-polygon form of Polygon (presently?) renders without antialiasing by default this also works:

Graphics[{Polygon[{{{0, 0}, {1, 0}, {0, 1}}, {{1, 0}, {0, 1}, {1, 1}}}]}]

Reference:

Antialiasing -> False will do it, which surprisingly can be used in-line as a directive:

Graphics[{Antialiasing -> False, Polygon[{{0, 0}, {1, 0}, {0, 1}}], 
  Polygon[{{1, 0}, {0, 1}, {1, 1}}]}]

Because the multiple-polygon form of Polygon (presently?) renders without antialiasing this also works:

Graphics[{Polygon[{{{0, 0}, {1, 0}, {0, 1}}, {{1, 0}, {0, 1}, {1, 1}}}]}]

Reference:

Antialiasing -> False will do it, which surprisingly can be used in-line as a directive:

Graphics[{Antialiasing -> False, Polygon[{{0, 0}, {1, 0}, {0, 1}}], 
  Polygon[{{1, 0}, {0, 1}, {1, 1}}]}]

Because the multiple-polygon form of Polygon (presently?) renders without antialiasing by default this also works:

Graphics[{Polygon[{{{0, 0}, {1, 0}, {0, 1}}, {{1, 0}, {0, 1}, {1, 1}}}]}]

Reference:

added 129 characters in body
Source Link
Mr.Wizard
  • 273.1k
  • 34
  • 595
  • 1.4k

Antialiasing -> False will do it, which surprisingly can be used in-line as a directive:

Graphics[{Antialiasing -> False, Polygon[{{0, 0}, {1, 0}, {0, 1}}], 
  Polygon[{{1, 0}, {0, 1}, {1, 1}}]}]

Because the multiple-polygon form of Polygon (presently?) renders without antialiasing this also works:

Graphics[{Polygon[{{{0, 0}, {1, 0}, {0, 1}}, {{1, 0}, {0, 1}, {1, 1}}}]}]

Reference:

Antialiasing -> False will do it, which surprisingly can be used in-line as a directive:

Graphics[{Antialiasing -> False, Polygon[{{0, 0}, {1, 0}, {0, 1}}], 
  Polygon[{{1, 0}, {0, 1}, {1, 1}}]}]

Reference:

Antialiasing -> False will do it, which surprisingly can be used in-line as a directive:

Graphics[{Antialiasing -> False, Polygon[{{0, 0}, {1, 0}, {0, 1}}], 
  Polygon[{{1, 0}, {0, 1}, {1, 1}}]}]

Because the multiple-polygon form of Polygon (presently?) renders without antialiasing this also works:

Graphics[{Polygon[{{{0, 0}, {1, 0}, {0, 1}}, {{1, 0}, {0, 1}, {1, 1}}}]}]

Reference:

Source Link
Mr.Wizard
  • 273.1k
  • 34
  • 595
  • 1.4k
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