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Mar 9, 2016 at 18:05 history edited Michael E2 CC BY-SA 3.0
Added alternative
Mar 9, 2016 at 17:45 comment added Michael E2 @LuisNegrete Can you not do it in the same way? You may find Inactivate[expr, Dt] and Activate[] helpful if you're dealing with complicated expressions.
Mar 9, 2016 at 17:41 comment added Luis Negrete This is really useful. Do you know if there is a way to also combine Dt[x,a] and Dt[y,a] into Dt[x+y,a] so that I might do x+y->z, for example.
Mar 9, 2016 at 17:35 history answered Michael E2 CC BY-SA 3.0