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Jan 25, 2016 at 0:04 vote accept Cham
Jan 24, 2016 at 11:18 comment added Edmund @Cham You can use 0. + $MachineEpsilon instead of 0.001. This is the closest your computer can get to zero and a less arbitrary way of preventing ParametricPLot from plotting zero to zero.
Jan 24, 2016 at 11:13 history edited Edmund CC BY-SA 3.0
Added better non-zero start point.
Jan 24, 2016 at 1:08 comment added Cham @Evans, so what should be the proper way of parametrizing the animation ? My only concern here is the arbitrariness of the 0.001 delay value I'm using.
Jan 23, 2016 at 23:16 comment added N.J.Evans The problem is you're trying to make a parametric plot from {t,Max[0, u - .2],u}. When u=0, Max[0,u-0.2] evaluates to 0, then you're plotting from {t,0,0}, which parametric plot doesn't like.
Jan 23, 2016 at 17:01 comment added Edmund Yes. Version 10.3.1 Win 8.1 Pro 64 bit. A ParametricPlot of circle can start at zero with no issues. It seems that Animate does not like it to start at zero.
Jan 23, 2016 at 16:57 comment added Cham A bug ? Is it the same with your more recent version of Mathematica ?
Jan 23, 2016 at 16:56 comment added Edmund @Cham It errors if I use 0 or 0. as the start. Might be a bug.
Jan 23, 2016 at 16:55 comment added Cham My code appears to be working great ! :-) However, I still don't understand the delay of 0.001. Is it really necessary to add such an arbitrary delay to the animate defintion ?
Jan 23, 2016 at 16:54 history edited Edmund CC BY-SA 3.0
added 67 characters in body
Jan 23, 2016 at 16:49 comment added Cham Why the small delay of 0.001 ?
Jan 23, 2016 at 16:48 comment added Cham Wow, it's working ! Thanks. I'll have to study your answer.
Jan 23, 2016 at 16:46 history answered Edmund CC BY-SA 3.0