Timeline for How to solve coupled multi-variable polynomials?
Current License: CC BY-SA 3.0
8 events
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| Dec 24, 2015 at 19:46 | history | edited | Jack LaVigne | CC BY-SA 3.0 |
added 3711 characters in body
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| Dec 24, 2015 at 16:00 | comment | added | Jerry Guern | No, I mean the 1 in the first argument of PolynomialRemainder in the code line for q2, not q1. Read the line of code right after the line in my question about generalizing. | |
| Dec 24, 2015 at 15:45 | comment | added | Jack LaVigne |
Your posted question addresses NSolve rather than Solve. Solve is giving the correct answer. If you numerically evaluate them some answers appear wrong. In particular solution[[5]]. {q1, q2} /. N[solution[[5]]] is bad. It turns out that this is a matter of precision. {q1, q2} /. N[solution[[5]], 30] gives the correct solution.
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| Dec 24, 2015 at 15:42 | comment | added | Jack LaVigne |
I think you meant replace 1 in q1 with t rather than q2. I don't see a 1 in q2. I tried replacing 1 in q1 with t and Solve spit out a result but I don't think there is any hope of being able to plot it.
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| Dec 24, 2015 at 3:49 | comment | added | Jerry Guern | Actually, this is returning incorrect results. I posted a Question about it. | |
| Dec 24, 2015 at 0:27 | comment | added | Jerry Guern | It also really surprised me that this returns complex roots that aren't paired with their complex conjugate. I know that if a single-variable polynomial has real coefficients, it's complex roots will be paired with their conjugate. Was I confused when I expected that here? | |
| Dec 24, 2015 at 0:26 | comment | added | Jerry Guern | Oh, I was trying to eliminate p and didn't think of just solving for {c,p} as a pair. Any thoughts on the generalization part, so I can plot c[t] where Abs[t] in some reasonable time? | |
| Dec 24, 2015 at 0:07 | history | answered | Jack LaVigne | CC BY-SA 3.0 |