Currently, from a variety of examples, and (mostly) the template generated by my IDE, I get:
(* Mathematica Package *)
(* :Title: MyPkg *)
(* :Context: MyPkg` *)
(* :Author: Me *)
(* :Date: 2015-12-17 *)
(* :Package Version: 0.3 *)
(* :Mathematica Version: 10.3 *)
(* :Copyright: (c) 2015 Me *)
(* :Keywords: *)
(* :Discussion: *)
(* USAGE:
SetDirectory[NotebookDirectory[]];
Get["MyPKg`"];
*)
BeginPackage["MyPkg`"]
Unprotect@@Names["MyPkg*"];
ClearAll@@Names["MyPkg*"];
MyPkg::usage = "Test package";
f::usage = "Solve it";
g::usage = "Show the puzzle";
(* ::Package:: *)
Begin["`Private`"]
(* ******************** Public exported functions and definitions *)
f[x_] := p[x]/2;
g[x_] := f[x] + q[x];
(* ******************** Internal supporting functions and definitions *)
p[x_] = x + 5;
q[x_] = x + 10;
End[] (* `Private` *)
EndPackage[]
But I'm confused about whether this is the right structure, or whether it does what I expect it to. Specifically:
- Is it really necessary or correct to define the package name in so many places? In the example, I have it in
Title
,Context
, andBeginPackage
, which seems redundant and prone to error. - How do I ensure that reimports of my package (with
Get
reliable clear the symbols defined there before defining them again. I'v seem several different approaches, but while,Unprotect@@Names["MyPkg*"];
andClearAll@@Names["MyPkg*"];
seem the most common, the don't seem to do anything. (And note again: I've had to specify the package name explicitly; is there a way to avoid that?) - What is
(* ::Package:: *)
for? Where should it go? I can't find that documented anywhere. - And what good is does the distinction among public, private, and exported symbols do anyway? If I
?"GCHQ`*"
I see all of them, even those that are private or local! - Some examples show ("protected") definitions between
End[] (*
andPrivate
*)EndPackage[]
; what goes there?
Any other tips on the correct structure for a package would also be appreciated. I can't seem to find consistent documentation on this, and much of what I can find is surpassingly old.