Suppose I have
v[x_] = (1.453 Sech[x + 1])^2 + I Sech[x + 1] Tanh[x + 1]
And I have to solve the equation:
mu1 u1[x] - u1''[x] - v[x] u1[x] == 0
for u1[x]
. The conditions that are given are:
u1[-2] == 1, u1'[-2] == 0 .
I have tried DSolve
but it shows errors:
Solve::inex: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help.
How can I Solve this equation in Mathematica symbolically?
Square
) on stackoverflow, so you should have corrected it before posting here. Do you realize that thisv
is a complex-valued potential because it containsI
? Just to make sure this isn't a mistake too. The problem you're having is probably that you're supposed to adjust the value ofmu1
so that another boundary condition is satisfied, presumably at somex > -2
. Only with that additional information will this become an eigenvalue problem. $\endgroup$