780 reputation
2528
bio website
location Seattle, WA
age 70
visits member for 2 years, 3 months
seen 41 mins ago

I retired in 2006 and bought Mathematica and a stack of math books with the goal to teach myself to become a world-class mathematician. I am on pace to achieve that goal sometime shortly after the next Ice Age.

I consider myself a Mathematical Mutt (no papers) who occasionally ventures off the back porch to play in the yard with the big dogs.

I donate regularly to the The OEIS Foundation.

When I look at the patterns, I can hear the wheels turning. When I look at the math, I find out the hamsters have died.


Dec
29
accepted Precision differences
Dec
28
comment Precision differences
Sum[(1/k^2 + 1/(k^2 - k)), {k, 2, Infinity}] - Zeta[2] Here I changed the minus to a plus.
Dec
28
comment Precision differences
I misunderstood. Change the $-$ between the two terms to a $+$ to get zeta[2].
Dec
28
comment Precision differences
The second one---1/k^2 (but starting with k=1).
Dec
28
comment Precision differences
+1, because I replaced the constant one with a sum that converges to one, this might be a pathelogical example. The pronic numbers may converge to one at a different rate than zeta[2] converges.
Dec
28
comment Precision differences
If you check the link provided by Nasser M. Abassi just below the OP, you will find he got exact values using Maple16.
Dec
28
comment Precision differences
@NasserM.Abbasi, thanks for that effort. I think I have a bug. I'm in v.8
Dec
28
revised Precision differences
to show a similar excentricity
Dec
28
comment Precision differences
+1, Does this mean that the limit is the correct value and if I want to compare the digits I should use the symbolic value?
Dec
28
asked Precision differences
Dec
22
comment What causes this strange convergent sum?
Is there any reason that PolyGamma is used for this number as opposed to the first number?
Dec
22
accepted What causes this strange convergent sum?
Dec
22
asked What causes this strange convergent sum?
Dec
20
revised How can I improve this trial division procedure?
added latex description of recursion
Dec
19
comment How can I improve this trial division procedure?
@DanielLichtblau, I put the new functions in the OP. The second one allows me to use a list of divisors, which can be primes or all numbers below the square root.
Dec
18
revised How can I improve this trial division procedure?
to show new functions
Dec
18
comment Are you interested in purchasing David Wagner's “Power programming with Mathematica”?
I will buy one.
Dec
18
accepted How can I improve this trial division procedure?
Dec
18
comment How can I improve this trial division procedure?
Very nice! Should be easy to explain in the paper.
Dec
18
asked How can I improve this trial division procedure?