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 Nice Answer
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Dec
9
accepted Why the strange limit?
Dec
7
comment Why the strange limit?
@Graumagier, make that an answer so I can sign off on it.
Dec
7
asked Why the strange limit?
Sep
11
comment Why does Wolfram Alpha not return a solution to this problem involving Floor[]?
@PatrickStevens, very nice!
Sep
11
comment Why does Wolfram Alpha not return a solution to this problem involving Floor[]?
@VividD, see my update for possible solution.
Sep
11
revised Why does Wolfram Alpha not return a solution to this problem involving Floor[]?
added better hints
Sep
11
answered Why does Wolfram Alpha not return a solution to this problem involving Floor[]?
Sep
11
revised Infinite product for Zeta[2]?
added link
Sep
11
revised Infinite product for Zeta[2]?
fixed the first expression
Sep
10
awarded  Nice Question
Sep
10
accepted Infinite product for Zeta[2]?
Sep
8
comment Infinite product for Zeta[2]?
@Dr.WolfgangHintze, Thanks for the heads-up re: $s.$ The interesting pattern is that the prime product uses primes only. We use multiples of $4,6$ which are the mid-points where odd primes can occur. As soon as I get my activation code for Mathematica later today, I plan to look at both functions to see the differences/commonalities. It might not be special?
Sep
8
revised Infinite product for Zeta[2]?
fixed syntax, replace $s$ with $2$
Sep
8
revised Infinite product for Zeta[2]?
added comment about periodic cycle. removed previous comment
Sep
8
revised Infinite product for Zeta[2]?
added comment about twin primes
Sep
8
answered Infinite product for Zeta[2]?
Sep
7
comment Infinite product for Zeta[2]?
@Dr.WolfgangHintze, It's the Euler product using multiples of 6.
Sep
7
comment Infinite product for Zeta[2]?
+1 for nice plot. I've learned something new.
Sep
7
comment Infinite product for Zeta[2]?
@Dr.WolfgangHintze, A few years ago I found a product that produced $\frac{\pi}{3}$ using multiples of $6.$ Yesterday I decided to square it and insert something to multiply by $\frac{3}{2}$. It seems to work.
Sep
7
asked Infinite product for Zeta[2]?