Fred Kline
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 Dec 9 accepted Why the strange limit? Dec 7 comment Why the strange limit? @Graumagier, make that an answer so I can sign off on it. Dec 7 asked Why the strange limit? Sep 11 comment Why does Wolfram Alpha not return a solution to this problem involving Floor[]? @PatrickStevens, very nice! Sep 11 comment Why does Wolfram Alpha not return a solution to this problem involving Floor[]? @VividD, see my update for possible solution. Sep 11 revised Why does Wolfram Alpha not return a solution to this problem involving Floor[]? added better hints Sep 11 answered Why does Wolfram Alpha not return a solution to this problem involving Floor[]? Sep 11 revised Infinite product for Zeta[2]? added link Sep 11 revised Infinite product for Zeta[2]? fixed the first expression Sep 10 awarded Nice Question Sep 10 accepted Infinite product for Zeta[2]? Sep 8 comment Infinite product for Zeta[2]? @Dr.WolfgangHintze, Thanks for the heads-up re: $s.$ The interesting pattern is that the prime product uses primes only. We use multiples of $4,6$ which are the mid-points where odd primes can occur. As soon as I get my activation code for Mathematica later today, I plan to look at both functions to see the differences/commonalities. It might not be special? Sep 8 revised Infinite product for Zeta[2]? fixed syntax, replace $s$ with $2$ Sep 8 revised Infinite product for Zeta[2]? added comment about periodic cycle. removed previous comment Sep 8 revised Infinite product for Zeta[2]? added comment about twin primes Sep 8 answered Infinite product for Zeta[2]? Sep 7 comment Infinite product for Zeta[2]? @Dr.WolfgangHintze, It's the Euler product using multiples of 6. Sep 7 comment Infinite product for Zeta[2]? +1 for nice plot. I've learned something new. Sep 7 comment Infinite product for Zeta[2]? @Dr.WolfgangHintze, A few years ago I found a product that produced $\frac{\pi}{3}$ using multiples of $6.$ Yesterday I decided to square it and insert something to multiply by $\frac{3}{2}$. It seems to work. Sep 7 asked Infinite product for Zeta[2]?