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 Jan 5 reviewed Close Sharing an axis between two plots Jan 4 reviewed Leave Open Lorenz map for the Rössler system Jan 4 reviewed Close How to use the same color bar for different DensityPlot Jan 4 comment How to get exact roots of this polynomial? @minthao: Those roots are exact. What you seem to mean, then, is that you wish to identify some of the roots with some of the roots of another (unspecified) polynomial (which is how those cosines are defined). Jan 4 revised How to get exact roots of this polynomial? deleted 26 characters in body; edited title Jan 4 comment How to get exact roots of this polynomial? @b.gates And the next two steps are to let $x\to z/2$ to clear out powers of $2$ and then to take the big factor, $p(z)=1+3 z-3 z^2-4 z^3+z^4+z^5$ and symmetrize it via $p(z+1/z)z^5$: the primitive eleventh roots of unity pop right out. Jan 2 comment Turn list of edges into a polygon function @Daniel The example output is an intersection of half-planes, which can describe only a convex figure. Jan 2 comment Turn list of edges into a polygon function The type of example you give will work only for convex polygons. Is that a fair assumption to make in your application? If so, may we also assume the vertices have already been sorted in the order they appear around the polygon's boundary, and that the sorting follows a conventional orientation (such as keeping the interior of the polygon always to the left)? A solution for non-convex polygons can be obtained but would require more work (equivalent to triangulating them). Is it possible you only need some procedure to solve the point-in-polygon problem? Jan 2 reviewed Leave Open Domain Coloring Jan 2 reviewed Close Problem with SphericalPlot3D plotting Dec 28 comment How to represent a list as a cycle @Mr Very nice! I understand that your second method selects the lexicographically earliest representative of the class of all rotations of a list and then replaces any list by its representative. Because that is far superior in timing to the (quadratic) pattern-matching solution I posted, I'm deleting that solution. Dec 28 comment How to visualize 3D fit +1. It is useful at this stage to plot the residuals against the fit: that will make your comments more precise. BTW, fit["FitResiduals"] is a built-in way to obtain the residuals. Dec 28 comment How to visualize 3D fit A standard--and very effective--way to show the fit is to plot the residuals (equal to actual - estimated) against $x$ and $y$. For a good fit they should cluster evenly and randomly around the $xy$ plane. Because there's no question about where that plane lies, you don't even need the third dimension. For instance, many people map out the residuals in 2D using scaled and/or colored point symbols to represent their sizes and signs. Dec 26 revised Define Log so that negative reals evaluate on lower edge of branch added 154 characters in body Dec 26 comment Using Transpose with a list as the second argument +1 I am thinking the illustrations might work even better with some color coding. E.g., colors[1, 1] = Darker[Red]; colors[1, 2] = Darker[Green]; colors[1, 3] = Darker[Blue]; colors[2, 1] = Lighter[Red]; colors[2, 2] = Lighter[Green]; colors[2, 3] = Lighter[Blue]; f[x_] := Replace[MatrixForm[x], Subscript[a, i_, j_, k___] -> Style[Subscript[a, i, j, k], colors[i, j]], -1]; f[A], etc. Dec 26 comment How do I expand a sum? You are requesting two changes: first to Expand the products in the summation and second to Distribute the action of Sum over the addition. Consulting the help pages for Expand and Distribute will answer your question. Dec 26 answered Define Log so that negative reals evaluate on lower edge of branch Dec 24 revised How do I solve this equation? Removed a potentially deceptive term from the title (this is not a functional equation). Dec 21 comment Can Depth be used as an equivalent for MatrixQ? @jVincent I do not know why you are addressing that last comment to me: I have not written anything here about lack of knowledge, intuition, FullForm, f[x_], or anything else you mention, nor have I ever suggested that the status of this question should be resolved based on our guesses about the O.P.'s state of mind. I have explained why I think this question, based on its merits, needs improvement, without resorting to any speculation about the knowledge or background of the person who asked it. (And--unlike 7 other people--I have not downvoted it.) Dec 21 reviewed Leave Closed Can Depth be used as an equivalent for MatrixQ?