346 reputation
7
bio website
location
age
visits member for 8 months
seen Apr 2 at 2:57

Mar
7
accepted How to do this complex integration on the real line?
Mar
7
comment How to do this complex integration on the real line?
@Artes Thanks! But I do not think that post helpful, because the result here is a Bessel function and the integration is already on the real line.
Mar
7
comment How to do this complex integration on the real line?
@DanielLichtblau Thanks! I update the question.
Mar
7
revised How to do this complex integration on the real line?
added 84 characters in body
Mar
6
revised How to do this complex integration on the real line?
added 354 characters in body
Mar
6
revised How to do this complex integration on the real line?
omit z
Mar
6
comment How to do this complex integration on the real line?
@b.gatessucks Yeap! Thanks! But how to do the new integration?
Mar
6
asked How to do this complex integration on the real line?
Feb
27
accepted CoordinateTransformData that works for any dimension
Feb
27
asked CoordinateTransformData that works for any dimension
Jan
8
accepted How can I define a ⊕ operator?
Jan
8
comment How can I define a ⊕ operator?
"When you attempted the second one, the kernel already knew something about the head and try to evaluate it and got Function", can we avoid this?
Jan
8
comment How can I define a ⊕ operator?
Thanks for your wonderful answer! But we should wait for @rm-rf waking up. He has promised to give an answer.
Jan
8
comment How can I define a ⊕ operator?
@rm-rf Thanks! Can you analyze the error in my original code to teach me a lesson?
Jan
8
revised How can I define a ⊕ operator?
added 107 characters in body
Jan
8
comment How can I define a ⊕ operator?
@belisarius Thanks! Can you explain why? and I want to define the operation \[CirclePlus] like +,-,*,/ which can be used as a \[CirclePlus] b.
Jan
8
asked How can I define a ⊕ operator?
Jan
7
comment How to form a block-diagonal Matrix from a list of matrices?
What's wrong with CirclePlus := SparseArray[Band[{1, 1}] -> {##}] &; a_\[CirclePlus]b_ := CirclePlus[a, b]
Jan
2
accepted How to convert the expression '{a->a0, b->b0}' to the expression 'a=a0; b=b0'?
Jan
2
comment How to convert the expression '{a->a0, b->b0}' to the expression 'a=a0; b=b0'?
@Nasser Thanks! I update the question.